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torque example problems with solutionsThe formula for torque is: τ = r x F = rFsinθ. So for an angle of 60 0: τ = (0.84 m) (45 N) sin (60 0) = 32.7 Nm = 33 Nm. If the force is applied at an angle of 90 0 to the radius, the sin factor θ becomes 1, then the torque value is: τ = rF = (0.84 m) (45 N) = 37.8 Nm = 38 Nm. Problem #2.
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